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Class-10

বৰগীত || Lesson – 1 || Class 10 Question Answers

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বৰগীত || Lesson – 1 || Class 10 Question Answers কবি পৰিচয় :

শ্ৰী শ্ৰী মাধৱদেৱ : নৱ বৈষ্ণৱ ধৰ্মৰ অন্যতম প্ৰচাৰক শ্ৰী শ্ৰী মাধৱদেৱৰ জন্ম হৈছিল লক্ষীমপুৰ জিলাৰ নাৰায়ণপুৰৰ লেটেকু পুখুৰীত ১৪৮৯ চনত জন্ম হয়। তেওঁৰ পিতৃ গোবিন্দ গিৰী ভূঞা আৰু মাতৃ মনোৰমা । শঙ্কৰদেৱৰ প্ৰীয় শিষ্য মাধৱদেৱ গুৰুক পদাংককে অনুসৰণ কৰে । তেওঁ গণককুছি , সুন্দৰী দিয়া ভেলা দংগা আদিত ধৰ্ম প্ৰচাৰ কৰিছিল । ধৰ্ম প্ৰচাৰৰ লগতে সাহিত্য সংস্কৃতিৰো পূজাৰী এইজনা মহান গুৰুৰ সাহিত্যিক জীৱনৰ কীৰ্তি স্তম্ভ হল ‘ নামঘোষা ‘ , এহেজাৰটা ঘোষা থকা বাবে এইজনাক হেজাৰী বুলি কোৱা হয় । তেওঁৰ আন আন ৰচনা সমুহ হল –
*আখ্যান মূলক ৰচনা* – ৰাজ সুয় কাব্য, আদিকাণ্ড ৰামায়ণ ।
*তত্ত্ব মূলক ৰচনা* – জন্ম ৰহস্য, ভক্তি – ৰত্নাবলী, নাম মালিকা
*নাট* – অৰ্জুন ভঞ্জন বা দধিমথন

মহাপুৰুষ শ্ৰীমন্ত শঙ্কৰদেৱৰ দ্বাৰা প্ৰচাৰিত বৈষ্ণৱ ধৰ্মক সাধাৰণ মানুহৰ অধিক কাষ চপাই নিয়াৰ অৰ্থে মাধৱদেৱ তেওঁৰ ৰচনা ৰাজিত ঘৰুৱা ভাৱ – ভাষা ব্যৱহাৰ কৰি তাৰ জৰিয়তে জনসাধাৰণক বৈষ্ণব ধৰ্মৰ তত্ত্ব সমূহ সহজে বুজি পোৱাত সহায় কৰিছিল । এই গীতটি মাধৱদেৱৰ ভক্তিৰ উৎকৃষ্ট নিদৰ্শন ।

বৰগীতৰ লক্ষণ সমূহ :

১) বৰগীত সমূহ শাস্ত্ৰীয় ৰাগ তালযুক্ত গীত ।
২) বৰগীতৰ ভাষা ব্ৰজাৱলী ।
৩) বৰগীত সমূহ ভক্তিমূলক তথা ঈশ্বৰৰ মহত্ব প্ৰকাশক ।
৪) শংকৰ মাধৱ লিখা গীতসমূহক বৰগীত বোলা হয় । নামধৰ্ম প্ৰচাৰৰ উ্দেশ্যে বৰগীত সমূহ ৰচিত ।
৫) বৰগীত সমূহ মূলত ভক্তি ৰস প্ৰধান যদিও তাত দশ্যো শান্ত বাৎসল্লো আদি ৰসৰে সমাবেশ ঘটিছে ।
৬) মাধৱদেৱৰ বৰগীত সমূহ ঘাইকৈ শ্ৰী কৃষ্ণৰ লীলা বিষয়ক ।

SEBA HSLC Examination Previous Year’s Question & Answers – click here


ব্ৰজাৱলী ভাষা :

ব্ৰজাৱলী ভাষা একপ্ৰকাৰৰ কৃত্ৰিম সাহিত্যিক ভাষা , শঙ্কৰদেৱৰ সময়ত অসম , বংগ আৰু উৰিষ্যাত এটা কৃত্ৰিম ভাষাৰ মাধ্যমত ভগৱান শ্ৰী কৃষ্ণৰ লীলা বিষয়ক গীত পদৰ সৃষ্টি হৈছিল, এই সাহিত্যিক ভাষাক ব্ৰজবুলি , ব্ৰজবলে আৰু অসমীয়াত ব্ৰজাৱলী ভাষা বোলা হয় ।
পশ্চিম হিন্দীৰ অপভংশ্ৰ ভাষাৰ লগত ইয়াৰ কোনো সম্পৰ্ক নাই । ব্ৰজাৱলী ভাষাৰ মূল ভেটি মৈথিলী । তাৰ লগত ভোজপুৰী নেয়াৰী আৰু কাষৰীয়া অঞ্চলৰ আন ভাষাৰ সংমিশ্ৰণে ই ঠাই বিশেষ একোটা স্বতন্ত্ৰ ৰূপ লাভ কৰে । ব্ৰজাৱলী ভাষা এহাতে শক্তিশালী আৰু স্বৰধ্বনি অধিক প্ৰয়োগৰ বাবে শ্ৰুতিমধুৰ । বৰগীত || Lesson – 1 || Class 10 Question Answers

ভাৱ বিষয়ক প্ৰশ্ন উত্তৰ :

১) চমুকৈ প্ৰশ্নৰ উত্তৰ দিয়া :

ক) ” ….. নেৰিব বান্ধব মোক জীৱনে মৰণে । “
– কবিয়ে জীৱনে মৰনে নেৰিবৰ বাবে কাক অনুৰোধ কৰিছে ?
উত্তৰ : শ্ৰী কৃষ্ণক

খ) ‘ সনক – সনন্দ যোগী যাহাকু বিধায়।’
– সনক – সনন্দ যোগী সকলে কাক ধ্যান কৰে বুলি কৈছে ?
উত্তৰ : সনক – সনন্দ যোগী সকলে শ্ৰী কৃষ্ণৰ ধ্যান কৰে বুলি কৈছে ।

গ) কবি কিহঁত আতুৰ হোৱা বুলি কৈছে ?
উত্তৰ : বিষয় বাসনাত।

ঘ) বৰগীত টো কোনে ৰচনা কৰা ?
উত্তৰ : শ্ৰী শ্ৰী মাধৱদেৱৰ।

ঙ ) বৰগীতটি কি ৰাগত বন্ধা আছে ?
উত্তৰ : বসন্ত

চ ) কবিয়ে বান্ধব বুলি কাক কাক সম্বোধন কৰিছে ?
উত্তৰ : শ্ৰী কৃষ্ণক

ছ) ‘ মোহ পাশ ‘ মানে কি ?
উত্তৰ : মায়াৰ বান্ধোন ।

Assamese Essay Section – click here

২) বৰগীতৰ মূলভাৱ লিখা :

উত্তৰ : পাঠত উল্লেখিত শ্ৰী শ্ৰী মাধৱ দেৱ বিৰচিত বসন্ত ৰাগত বন্ধাবৰ গীতটিত মাধৱদেৱৰ ভক্তিৰ উৎকৃষ্ট নিদৰ্শন দেখিবলৈ পোৱা যায়।

কবিয়ে উল্লেখ কৰিছে যে শ্ৰী কৃষ্ণ হল সকলোৰে পিতৃ স্বৰূপ, জীৱনে মৰণে তেওঁক যেন কেতিয়াও নেৰে তাৰ বাবে তেওঁ ভগবানৰ চৰণত শৰণ লৈছে । সনক সনন্দ যোগী সকলে যাক ধ্যান কৰে, সহস্ৰ বাৰ জন্ম গ্ৰহণ কৰি ও যাৰ অস্তিত্বৰ সীমা বিচাৰি পোৱা নাযায়, সেই জন পৰম ব্ৰহ্মাক তেওঁ নিছিনা সাধাৰণ মানুহে কি বুজিব, হৰিৰ মহিমা অপাৰ । বিষয় বাস নাত মত্ত হৈ থাকি তেওঁক বুজিব নোৱাৰি, সেয়েহে এই মায়াময় সংসাৰৰ পৰা শ্ৰী কৃষ্ণই অৰ্থাৎ হৰিয়ে উদ্ধাৰ নকৰিলে কোনেও উদ্ধাৰ কৰিব নোৱাৰে ।

গতিকে শ্ৰী কৃষ্ণৰ চৰণেই হৈছে মহাধন তেৱেঁই হৈছে ভক্ত সকলৰ জীৱন, ভক্ত সকল নিজৰ অজ্ঞতে নানা ভুল ভ্ৰান্তি কৰে, কৃপাৰ সাগৰ স্বৰূপে কৃষ্ণই দয়া নকৰিলে আন কোনেও মুক্তি দিব নোৱাৰে । সেইকাৰণে শ্ৰী কৃষ্ণৰ চৰণত শৰণ লোৱাৰ বাহিৰে অইন উপায় নাই । শেষত মাধৱদেৱে কাতৰ ভাবে প্ৰাৰ্থনা জনাইছে শ্ৰী কৃষ্ণই যাতে এই মায়া মোহৰ বান্ধোনৰ পৰা তেওঁক মুক্ত কৰে আৰু তাৰ বাবে তেওঁ দাসৰ দাস হৈ শ্ৰী কৃষ্ণৰ চৰণত নিজকে সমৰ্পণ কৰিছে ।বৰগীত || Lesson – 1 || Class 10 Question Answers

৪) বাখ্যা কৰা :

ক) সহস্ৰ বয়নে যাৰ নপাবন্ত সীমা
অধমে জানিব কেনে তোমাৰ মহিমা ।

উত্তৰ : উদ্ধৃত পদফাকি আমাৰ পাঠ্য পুথিৰ অন্তৰ্গত মাধৱদেৱ ৰ বিৰচিত বৰগীত ৰ পৰা তুলি দিয়া হৈছে ।

ইয়াত শ্ৰী কৃষ্ণৰ মহিমা সাধাৰণ মানুহে যে বুজা টান সেই বিষয়ে কবলৈ যোৱাৰ প্ৰসঙ্গত উক্ত পদ ফাকিৰ অৱতাৰণা কৰিছে ।

শ্ৰী কৃষ্ণৰ মহিমা অপাৰ, এই বিশ্বৰ প্ৰতিটো বস্তুতে তেওঁৰ স্থিতি বৰ্তমান, তেওঁক বাদ দি পৃথিৱীৰ কল্পনা কৰিব নোৱাৰি । সনক – সনন্দ আদি যোগীসকলেও যাক প্ৰানত ধ্যনত লাভ কৰিব পৰা নাই তেনে স্তৰত কবিৰ দৰে সাধাৰণ মানৱে তেওঁৰ মহিমা কি বুজি পাব , ভগৱানক লাভ কৰিবলৈ হলে একান্ত সাধনাৰ প্ৰয়োজন । এই জগতখন হৈছে মায়াময়, এই সংসাৰৰ পৰা পৰিত্ৰাণ পোৱা সাধাৰণ মানুহৰ পক্ষে সম্ভৱ নহয়, সেয়েহে কবিয়ে কৈছে যে একমাত্ৰ ভগবানৰ শৰণাপন্ন হলেহে মায়াৰ সংসাৰৰ পৰা পৰিত্ৰাণ পাব পাৰি ।

খ ) আতুৰ ভৈলাহো হৰি বিষয় কিকলে
কৰিয় উদ্ধাৰ মোক চৰণ কমলে ।

উত্তৰ : উদ্ধৃত পদফাকি আমাৰ পাঠ্য পুথিৰ অন্তৰ্গত মাধৱদেৱ ৰ বিৰচিত বৰগীত ৰ পৰা তুলি দিয়া হৈছে ।

ইয়াৰ জৰিয়তে কবিয়ে বিষয় বাসনাৰ ব্ৰতী হৈ তাৰ পৰা উদ্ধাৰ পাবৰ কাৰণে শ্ৰী কৃষ্ণৰ শৰণাপন্ন হোৱাৰ কথা বৰ্ণনা কৰিছে ।

মানুহে এই সংসাৰত মায়াত আবদ্ধ হৈ আছে, মায়াত আবদ্ধ হৈ থাকি মানুহে ঈশ্বৰৰ কথা নাভাবে, বিষয় বাসনাৰ আত্ম বিভোৰ হৈ মানুহে ভগৱানক বিচাৰি নাপায় । শেষত যেতিয়া মুক্তিৰ পথ বিচাৰি নাপায় তেতিয়াহে শেষ আশ্ৰয় হিচাপে শ্ৰী কৃষ্ণক বিচাৰে । সেয়েহে কবিয়ে বিষয় বাসনাৰ পৰা নিজকে মুক্ত কৰিবলৈ ভগবানৰ শৰণাপন্ন হবলৈ বিচাৰিছে, যাতে তেওঁ এই সংসাৰৰ পৰা উদ্ধাৰ পায় ।

গ) তোমাৰ চৰণ দুই মোৰ মহা ধন
ভকত জনেৰ নিজ তুমিছে জীৱন

উত্তৰ : উদ্ধৃত পদফাকি আমাৰ পাঠ্য পুথিৰ অন্তৰ্গত মাধৱদেৱ ৰ বিৰচিত বৰগীত ৰ পৰা তুলি দিয়া হৈছে ।

ইয়াৰ জৰিয়তে কবিয়ে ভক্ত সকলৰ জীৱন স্বৰূপ যে শ্ৰী কৃষ্ণ সেই কথা কব বিচাৰিছে ।

কবিয়ে কৈছে যে মানুহে সংসাৰত জন্ম লাভ কৰি বিষয় বাসনাৰ আবদ্ধ হয়, বিষয় বাসনাৰ আতুৰ হৈ থকা লোকে কেতিয়াও মুক্তি লাভ কৰিব নোৱাৰে । হৰিৰ মহিমা আমাৰ নিচিনা সাধাৰণ মানুহে বুজাটো টান । কবিৰ মতে কৃষ্ণৰ চৰনেই পৰম ধন, ভকত সকলৰো তেৱেঁই জীৱন । অন্তৰত ভগৱানৰ প্ৰতি একান্ত ভক্তি থাকিলে তেওঁক পাব পাৰি, গতিকে মায়াৰ বন্ধনৰ পৰা মুক্ত হৈ কৃষ্ণৰ চৰণ সেৱা কৰিলেহে মানৱে মুক্তিৰ পথ লাভ কৰিব পাৰে।

Financial Education in Assamese – click here


ঘ) সনক – সনন্দ যোগী যাহাকু বিধায়।’
সকল নিগমে যাক বিচাৰি নাপায় ।

উত্তৰ : উদ্ধৃত পদফাকি আমাৰ পাঠ্য পুথিৰ অন্তৰ্গত মাধৱদেৱ ৰ বিৰচিত বৰগীত ৰ পৰা তুলি দিয়া হৈছে ।

এই সংসাৰত মানুহে ময়াত আবদ্ধ হৈ থাকি ঈশ্বৰৰ কথা চিন্তা নকৰে কিন্তু তেওঁৰ কৃপা অবিহনে জীৱৰ মোক্ষ প্ৰাপ্তি নহয় । সনক – সনন্দ আদি যোগীসকলে পাৰ্থিৱ সুখ বিসৰ্জন দি শ্ৰী কৃষ্ণক ধ্যানত বিচাৰিছিল, কিন্তু তথাপিও কৃষ্ণক পোৱা নাছিল সেয়েহে কবিয়ে নিজকে অধম বুলি কৈ তেওঁৰ মহিমা ৰ কথা একো নাজানে বুলি কৈছে, কৃষ্ণৰ মহিমা অপাৰ, একমাত্ৰ ভক্তিৰেহে আৰাধনা কৰি তেওঁৰ মহিমা বুজিব পাৰি । ভক্তৰ মনোবাঞ্ছা পূৰণৰ বাবে তেওঁ নানা লীলা খেলা কৰে । কবিয়ে কৈছে যে ভকত সকলৰ আত্মা স্বৰূপে কৃষ্ণই বিৰাজ কৰি থাকে, তেওঁৰ কৃপাত হে জীৱৰ মোক্ষ প্ৰাপ্তি হয়।বৰগীত || Lesson – 1 || Class 10 Question Answers

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A Letter to God || Chapter 1 || Class 10 All Question Answers

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A Letter to God || Chapter 1 || Class 10 All Question Answers

1) What did Lencho hope for ?

Answer: Lencho hoped for a downpour or atleast a shower.

2) Why did Lencho say the raindrops were like ‘new coins’ ?

Answer: Lencho was an experienced farmar. He knew that atleast a shower would help him in yielding a good harvest. It would bring him prosperity. So, he felt the rain drops were like ‘new coins’.

3) How did the rain change ? What happened to Lencho’s field?

Answer: Suddenly a strong wind began to blow and along with the rain very large hailstones began to fall. Thus, the rain changed into a hailstorm
The hail rained for an hour, not a leaf remained on the trees. The corns in Lencho’s field was totally destroyed. The flowers were gone from the plants.

4) What were Lencho’s feeling when the hailstorm stopped?

Answer: When the hail stopped, Lencho’s soul was filled with sadness. He realised that everything was ruined by the hailstorm and nothing was left to feed his family for the entire year. He only could visualise the black future of his family.

5) Who or what did Lencho have faith in? What did he do?

Answer: Lencho have strong faith God. He believe that god’s eyes watch every thing, even what is deep in one’s conscious, Hence, he wrote a letter to God citing that he needs a hundred pesos to sow his field again that was destroyed by hailstorm.

6 ) Who read the letter?

Answer: The postmaster read the letter.

7) What did Postmaster do after reading the letter?

Answer: Initially the postmaster broke out into laughter, but soon he moved by the belief of Lencho in God and for not to shake Lencho’s faith in God, the postmaster collected money and sent it to Lencho signing the letter as God.

8) Was Lencho surprised to find a letter for him with money in it ? or Did Lencho try to find out who had send the money to him ? why? why not ?

Answer : Lencho was surprised to find a letter for him with money in it nor did he try to find out who had sent the money to him. It was because he was very confident and had firm faith in God that his request would be take care of by almighty.

9) What made Lencho angry ? or Why did Lencho become angry ?

Answer : When Lencho counted the money, he found only 70 pesos instead of 100 pesos demanded by him from GOD. He was sure that God could neither make a mistake in sending him less money , nor could he have denied Lencho what he had requested . So, he doubted the honesty of the post office employees and become angry.

10) Why does the post master send money to Lencho ? Why does he sign the letter as “GOD” ?

Answer : The postmaster was deeply moved by Lencho’s faith in God. So, in order to not to shake Lencho’s faith in God expressed the letter, so the post master sent money to him. The postmaster sign the letter as God because he felt it was very essential to convey a massage to Lencho that God had sent him the money and that God himself sign on it.

11) Who does Lencho think has taken the rest of the money ? What is the irony of the situation ?

Answer : Lencho thought the post office employees have taken rest of the money. The irony in this situation is that Lencho ends up suspecting those very people who have helped him in his crisis, in order not to shake his faith in God .

12) What kind of a person Lencho was ?

Answer : Lencho was a very hardworking and naive kind of person. He had a complete faith in God. A Letter to God || Chapter 1 || Class 10 All Question Answers

মানৱ বন্দনা || Lesson-2 || Class – 9; Assamese Question Answers – click here

Additional Question Answers of “A Letter to God ” for Mark – 1

1) Who was Lencho ?

Answer : Lencho was a farmar .

2) What was Lencho’s profession ?

Answer: Lencho’s profession was farming.

3) When did Lencho write a letter to God ?

Answer: Lencho wrote a letter to God when his crops were ruined in a hailstorm.

4) What dis Lencho asked for God in his letter ?

Answer: Lencho asked for a hundred pesos from God in his letter .

5) Where was Lencho’s house situated ?

Answer: Lencho’s house was situated in the crest of a low hill in a solitary valley.

6) What could be seen from the Lenchos house ?

Answer: From the height of Lencho’s house one could see the river and the field of ripe corn dotted with flowers.

7) What did Lencho cultivate ?

Answer: Lencho cultivated corn .

8 ) What always promised a good harvest ?

Answer:The field with ripe corn dotted with flowers always promised a good harvest .

9) What did Lencho do throughout the morning ?

Answer: Throughout the morning Lencho did nothing else but see the sky towards the north-east.

10) What was Lencho’s wife doing ?

Answer: The woman was prepaRING SUPPER ( DINNER )

11) What was the older boys of Lencho doing ?

Answer: The older boys of Lencho were working in the field .

12) What were the smaller boys of Lencho doing ?

Answer: The smaller boys of Lencho were playing near the house .

13) What could be seen approaching in The north-east sky ?

Answer: In the north-east sky huge mountain of clouds could be seen approaching .

14) How was the air during the rain ?

Answer: The air was fresh and sweet during the rain.

15) Why did Lencho go out when it started raining ?

Answer: When it started raining, Lencho went out of his house to have the pleasure of feeling the rain on his body . A Letter to God || Chapter 1 || Class 10 All Question Answers

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16 ) What the boys do when the hailstone began to fall ?

Answer: When the hailstone began to fall, the boys ran out to collect the stones that looked like frozen pearls .

17) How long did the hail rain ?

Answer: The rail rained for an hour.

18 ) How did the Lencho’s field look after the hailstorm ?

Answer: After the hailstorm Lencho’s field was white as like it covered with salt .

19) What was the only hope for Lencho ?

Answer: Only hope for the Lencho was the helpe from the God .

20 ) What did Lencho write on the envelope ?

Answer: Lencho ” To God” on the envelope .

21) What did Lencho do after going to the post office on his first day ?

Answer: At the post office Lencho placed a stamp on the letter and dropped it into the mailbox.

22) What kind of Person was the post master ?

Answer: The post master was an fat and amiable person .

23) How much money Lencho received though mail ?

Answer: Lencho received only 70 pesos through the mail.

24) What did Lencho call the post office employees ?

Answer: Lencho called the post office employees ” a bunch of crooks” .

25) Who handed the letter to Lencho ?

Answer: The post master handed the letter to Lencho .

A Letter to God || Chapter 1 || Class 10 All Question Answers
A Letter to God || Chapter 1 || Class 10 All Question Answers

Financial Knowledge in Assamese – click here

Additional Question Answers of “A Letter to God ” for Mark – 2/3

1) Describe where Lencho’s house was situated ? or Describe the location of Lencho’s house ?

Answer : Lencho’s house was situated on the crest of a low hill in a solitary valley. his house was surrounded with the river and the fields of ripe corn dotted with flowers that always promised a good harvest.

2) Describe the field of Lencho before the rain or hailstorm ?

Answer : Before the hailstorm, there was ripe corn dotted with flowers in Lencho’s field. It always promised a good harvest. The only thing Lencho need for his field was a downpour or atleast a shower .

3) Describe the destruction caused by the hailstorm in Lencho’s field ? or Describe the condition of Lencho’s field after the hailstorm ?

Answer : After the hailstorm, not a single leaf remained on the trees of Lencho’s field . The corns were totally destroyed . The flowers were gone from the plants . It seemed that a plague of locusts would have left more than this. The hail had left nothing .

4) How did Lencho console his family ?

Answer : After the destruction of Lencho’s field, Lencho and his family became very upset. But, they just had a single hope in their heart – The help from the God. Lencho console his family by saying that they should not be upset even though they seemed like a total loss.

5) What dis Lencho write in his first letter to God ?

Answer : In his first letter to God Lencho wrote that if God didn’t help him , he along with his family will die because of hunger that is why he needed 100 pesos from God in order to sow his field again and to live until the crop grow again because the hailstorm had left nothing in his fiels .

6) How did Lencho react after receiving the letter ?

Answer : After receiving the letter Lencho counted the money and was angry because it was 70 pesos instead of 100 pesos . He thought that post office employees might stole the rest of 30 pesos.

7) Why did Lencho write a second letter to God ?

Answer : Lencho had to write a second letter to God because through the mail he got 70 pesos instead of 100 pesos that was requested to God to send him. As he needed the said amount very much, so he wrote a second letter to god asking remaining 30 pesos directly through mail, so that post office employees won’t able to take money.

8) What did Lencho write in the second letter to God?

Answer : In his second letter to God, Lencho wrote that of the money that he had asked for , only 70 pesos had reached and receive by him . He requested to God to send him the rest , since he needed it very much. And also he requested God to send the money to him directly through mail instead of sending through post office employees . A Letter to God || Chapter 1 || Class 10 All Question Answers

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SEBA HSLC Previous Year Question Papers

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SEBA HSLC Previous Year Question Paper 

Board of Secondary Education, Assam (SEBA) will be Conduct High School Leaving Certificate (HSLC) Public Examination in Assam State Wide. Assam HSLC Public Exam go to Conduct Every year Month of March, SEBA Regulate, Supervise and Develop Secondary Education in the State of Assam,

বোৰ্ড অৱ ছেকেণ্ডাৰী এডুকেশ্যন, অসম (SEBA) য়ে অসম ৰাজ্যব্যাপী হাইস্কুল শিক্ষান্ত (HSLC) ৰাজহুৱা পৰীক্ষা অনুষ্ঠিত কৰিব।  প্ৰতি বছৰে মাৰ্চ মাহৰ মাহত ছেবাই অসম ৰাজ্যত মাধ্যমিক শিক্ষা নিয়ন্ত্ৰণ, তত্বাৱধান আৰু বিকাশ কৰে, 

Benefits of solving previous year’s Question paper 

There are many advantages of solving previous year’s Question paper  and practising with them. SEBA Class 10th question papers are of great use and add to the exam preparation. Let’s know why students should refer to these Assam HSLC sample papers.

  • Solving previous year’s Question paper  will help the students to know the question paper structure and difficulty level of the SEBA exam.

  • Solving previous year’s Question paper will let the students know the important topics and the marking scheme of the exam. This will help them in knowing the weightage per topic and prepare accordingly.

  • Solving previous year’s Question paper will help the students to solve the question paper in a stipulated time. This will prepare them well for the exam and let them know the amount of time required for attempting each section in the exam.

  • One of the best advantages of solving Assam HSLC  previous year’s Question paper is that it will infuse the time management skill in the students. Solving the previous year’s question papers will make them more efficient and help them in scoring high.

  • Solving previous year’s Question paper will also help the students to know the trend of questions asked in the exam.

বিগত বৰ্ষৰ প্ৰশ্নকাকত সমাধান কৰাৰ সুবিধা

  1. আগৰ বছৰৰ প্ৰশ্নকাকতখন সমাধান কৰি সেইবোৰৰ সৈতে অনুশীলন কৰিলে বহু সুবিধা আছে। SEBA Class 10th প্ৰশ্নকাকত বহুত উপযোগী আৰু পৰীক্ষাৰ প্ৰস্তুতিত যোগ দিয়ে। আহক জানো আহক কিয় ছাত্ৰ-ছাত্ৰীসকলে এই অসম HSLC নমুনা কাগজবোৰ চাব লাগে।
  2. বিগত বৰ্ষৰ প্ৰশ্নকাকত সমাধান কৰিলে ছাত্ৰ-ছাত্ৰীসকলে প্ৰশ্নকাকতৰ গঠন আৰু ছেবা পৰীক্ষাৰ অসুবিধাৰ স্তৰ জানিব পাৰিব।
  3. বিগত বৰ্ষৰ প্ৰশ্নকাকত সমাধান কৰিলে ছাত্ৰ-ছাত্ৰীসকলে পৰীক্ষাৰ গুৰুত্বপূৰ্ণ বিষয় আৰু নম্বৰ দিয়াৰ আঁচনি জানিব পাৰিব। ইয়াৰ ফলত তেওঁলোকে প্ৰতিটো বিষয়ৰ ওজন জানিব পাৰিব আৰু সেই অনুসৰি প্ৰস্তুতি চলাব।
  4. বিগত বৰ্ষৰ প্ৰশ্নকাকত সমাধান কৰিলে ছাত্ৰ-ছাত্ৰীসকলে নিৰ্দিষ্ট সময়ত প্ৰশ্নকাকত সমাধান কৰাত সহায় কৰিব। ইয়াৰ ফলত তেওঁলোক পৰীক্ষাৰ বাবে ভালদৰে প্ৰস্তুত হ’ব আৰু পৰীক্ষাৰ প্ৰতিটো শাখাৰ প্ৰচেষ্টাৰ বাবে কিমান সময়ৰ প্ৰয়োজন সেই বিষয়ে জানিব পাৰিব।
  5. অসম এইচ এছ এল চিৰ বিগত বৰ্ষৰ প্ৰশ্নকাকত সমাধান কৰাৰ এটা উত্তম সুবিধা হ’ল ই ছাত্ৰ-ছাত্ৰীৰ মাজত সময় ব্যৱস্থাপনাৰ দক্ষতাৰ সৃষ্টি কৰিব। বিগত বছৰৰ প্ৰশ্নকাকত সমাধান কৰিলে তেওঁলোক অধিক কাৰ্যক্ষম হ’ব আৰু উচ্চ নম্বৰ পোৱাত সহায়ক হ’ব
  6. বিগত বৰ্ষৰ প্ৰশ্নকাকত সমাধান কৰিলেও ছাত্ৰ-ছাত্ৰীসকলে পৰীক্ষাত সোধা প্ৰশ্নৰ ধাৰা জানিব পাৰিব।

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LIGHT:REFLECTION and REFRACTION

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 1.What is light?

Ans:Light is a form of energy which produces the sensation of vission.

2. What is beam?
Ans: A collection of rays moving in an organized manner is called beam.

3. What is photon?
Ans: Photon is a particle of light energy.

4.What is optics?What are the different kinds of optics?
Ans: The branch of physics that deals with the nature of light,it’s source, properties and effects is called optics. There are two kinds of optics.they are –
a) Physical optics.
b) geometrical optics.

5. How many types  are there?
Ans: There are three types of rays.they are-.
a) Divergent rays.
b) Convergent rays.
c) Parallel rays.

6. What do you mean by reflection of light?
Ans: The phenomenon in which a ray of light travels in a medium,comes back into the same medium when incident on a second medium is known as reflection of light.

7. State the laws of reflection.
Ans: a)The incident ray,the reflected ray and the normal at the point of incidence,all lie in the same plane.
b) The angle of incidence is always equal to the angle of reflection.

8. What is an image?what are the types of image and explain it.
Ans: When a number of rays starting from a point after reflection or refraction actually meet at or appear to do so at another point.the second point is called the image of the first.
There are two types of image.they are- Real image – The image formed by actual intersection of the reflected rays or refracted rays is called a real image. Virtual image – The image formed by imaginary intersection of reflected rays or refracted rays is called virtual image.

9. Mention differences between real and virtual image.
Ans: a) The real image is formed by actual intersection of the reflected rays.on the other hand,The virtual image is formed by imaginary intersection of the reflected rays.
b) Real image can be projected on a screen.but,The virtual image can not be projected on a screen.
c) Real image is always inverted with respect to an object.on the other hand, virtual image is always erect with respect to an object.

10. What is spherical mirror? What are the types of spherical mirror?
Ans: A spherical mirror is a mirror whose reflecting surface forms a part of a hollow sphre of glass.
spherical mirror are of two types -.
a) Concave mirror – If the reflecting surface is curve inwards and the outer bulged surface is silvered then the mirror is a Concave.
b) Convex mirror – If the reflecting surface is bulged outwards and inner hollow surface is silvered then the mirror is a convex.

11. Define the following terms with a respect to spherical mirror.
a)Pole – The central point of the reflecting surface is called the pole of the spherical mirror.
b) Centre of curvature – The centre of the sphere of which the mirror surface is a part is called the centre curvature of the spherical mirror.
c) Radius of curvature – The radius of the sphere of which the mirror surface is a part is called the radius of curvature of the spherical mirror.
d) Principal axis – The line that joints the centre of curvature of the spherical mirror with its pole is called the principal axis of the spherical mirror.
e) Principal focus – For a Concave mirror it is a point on the principal axis such that rays of light parallel to the principal axis converge to it after reflection in the mirror. This point is called principal focus.
f) Focal length – The distance from the principal focus to the pole of the spherical mirror is called the focal length of the mirror.
g) Focal plane – A plane perpendicular to the principal axis and containing the principal focus is called the focal plane of the spherical mirror.

12. Write the uses of Concave mirror and Convex mirror.
Ans: Concave mirror – a) Concave mirrors are commonly used in torches, search lights,and vehicles headlights to get powerful parallel beams of light.
b) Concave mirrors are used by dentists to see large images of the teeth of patients.
c) Concave mirrors are used as shaving mirrors to see a larger image of the face. d) Large concave mirrors are used to concentrate sunlight to produce heat in solar furnaces.
Convex mirror – a) Convex mirrors are commonly used as rear view mirrors in vehicles.
b) Convex mirrors are used as security mirrors in public buildings.
c) Convex mirrors are used in magnifying glass.
d) Convex mirrors are also used in making lenses of sunglasses.

13. What do you mean by magnification of an image?
Ans: Magnification produces by a spherical mirror gives the relative extent to which the image of an object is magnified with respect to the object size. It is expressed as the ratio of the height of the image to the height of the object.It is usually represented by the letter ‘m’
m = – Height of the image (h’) / Height of the object (h).
The Magnification m is also related to the object distance (u) and image distance (v).It can be written as :.
Magnification (m) = – h’/h = -v/u
sign convention for magnification
(i) Magnification is negative for real images (since such images are inverted). (ii) Magnification is positive for virtual images (since such images are erect).

14. What do you mean by refraction of light?
Ans: When light travels from one medium to another medium,it speed is changed . consequently,at the interface of two medium,the direction of the passing ray changed. The change of direction of the incident ray is called refraction of light.

15. State the laws of refraction.
Ans: Laws of refraction
(a) The incident ray, the refracted ray and the normal to the interface of two transparent media at point of incidence all lie in the same plane.
(b) For a particular pair of media the angle of incidence’ i’ in medium l is related to the angle of refraction ‘r’ in medium 2 by the relation-
n Sin i = n sin r or,
Sin i / sin r =constant.
The constant value is called the refractive index of the second medium with respect to the first.
The second law of refraction is called Snell’s law of refraction.

16. What do you mean by refractive index of medium?
Ans: The refractive index (n) of a transparent medium is the relation of the speed of light in vaccum (c) to the speed of light in that medium (v).
Refractive index = speed of light in vaccum / speed of light in medium.
* n= c/v.

17. What is a lens? Name two types of lenses.
Ans: A lens is a transparent medium bounded by two surfaces of which at least one is spherical.
Lenses can be classified into two categories –
(i) Convex or converging lenses:A lens which is thick at the centre but thinner at the edges is a convex lens. There are three types of convex lens-
a) Double convex lens or biconvex lens. b) plano-convex lens.
c) Convex meniscus.
(ii) Concave lens or diverging lenses: A lens which is thin at the centre but thicker at the edges is a Concave lens. There are three of concave lens –
a) Double concave lens or biconcave lens b) Plano concave lens.
c) Concave meniscus.

18. Define the following term in connection with lens.
a) Centre of curvature : The centre of curvature of the surface of a lens is the centre of the sphere of which it forms a part because a lens has two surfaces so it has two centres of curvature.
b) Radius of curvature : The radius of curvature of the surface of a lens is the radius of the sphere of which the surface forms a part.
c) Principal axis : It is the line passing through the two centres of curvature of the lens.
d) Optical centre : It is a point situated within the lens through which a ray of light passes undeviated.
e) Focal length : It is the distance between the principal focus and the optical centre of the lens.
f) Aperture : It is the diameter of the circular boundary of the lens.

19. Differences between Concave and a convex lens.
Ans: (i) Concave lens is thinner at the centre than the edges.and Convex lens is thicker at the centre than the edges.
(ii) Concave lens diverges a parallel beam of light on reflection through it.and Convex lens converges a parallel beam of light on refraction through it.
(iii) concave lens has a virtual focus.and convex lens has a real focus.

20. What do you mean by magnification of lens?
Ans: The magnification produced by a Lens, similar to that for spherical mirrors,is derived as the ratio of the height of the image and the height of the object.It is represented by the letter ‘m’ .If h is the height of the object and h’ is the height of the image given by lens,then the magnification produced by the lens is given by,
m = Height of the image / Height of the object = h’ / h.
Magnification produced by a lens is also related to the object (u) and the image distance (v).
This relationship is given by Magnification (m) = h’ / h = v / u.

21. Define the power of lens. What is its SI unit?
Ans: The ability of a convex lens to converge a parallel beam of light to point near the lens or the ability of a Concave lens to make the beam appear to diverge from a nearby point known as the power of the lens . If P denotes the power of. Lens of focal length f meter, then.               
P = 1 / f The SI unit of power lens is dioptre. It is denoted by the letter D. If f is expressed in metres, then power is expressed in dioptre.






TEXTUAL QUESTIONS




1. Define the principal focus of a concave mirror .
Ans: It is a point on the principal axis where the rays of light parallel to principal axis meet.

2. The radius of curvature of spherical mirror is 20 cm. What is its focal length?
Ans: Focal length=1/2 × Radius of curvature
=1/2 × 20 cm
=10 cm

3. Name a mirror that can give an erect and enlarged image of an object.
Ans : Concave miror.

4. Why do we prefer a convex mirror as a rear-view mirror in vehicles?
Ans: Convex mirror can cover a wider range and give erect and diminished image Hence convex mirror is used as a rear-view miror to get wider field of view.

5.Find the focal length of a convex mirror whose radius of curvature in 32Cm.
Ans: As the radius of curvature and focal length of a convex mimor are positive, so
R = +32 cm
f  = R/2
   =16 cm.

6. A concave mirror produces three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Where is the image located?
Ans : Object distance, u =-10 cm (concave mirror),
magnification, m=-3
                  m=-v/u
therefore,v = – mu
                      =- (-3) (-10)
                      =-30cm.
Image formed, v = 30 cm in front of the concave mirror.

7. A ray of light travelling in air enters obliquely into water. Does the light ray bend towards the normal or away from the normal? Why?
Ans: Light trends faster in rarer medium (air) and slower in denser medium (water). As a ray of light traveling in air enters obliquely into water, it slows down and bends towards the normal.

8. Light enter from air to glass having refractive index 1.50. What is the speed of light in the glass? The speed of light in vacuum is 3×10⁸ m/s.
Ans: The speed of light in vacuum is 3×10⁸ m/s.
Refractive index of glass = 1.50
n= C/V
speed of light in glass, v ,= C/h
                                              =3×10 g /1.50
                                              =2 × 10⁸ m/s.

9. Find out, from table 10.3 the medium having highest optical density. Also find the medium with lowest optical density.
Ans: Diamond has highest refractive index ( 2.42), so it has largest optical density.
Air has lowest refractive index (= 1.0003), so it has lowest optical density.

10. You are given Kerosene, turpentine and water In which of these does the light travel fastest? Use the information given in table 10.3.
Ans: Refractive index of Kerosene=1.44
Refractive index of Turpentine.    =1.47 Refractive index of water               =1.33 Lower the refractive index faster in the speed of light in that medium. Hence, light will travel fastes in water.

11. The refractive index of diamond is 2.42. What is the meaning of this statement?
Ans: The refractive index of diamond is 2 .42 It indicates that the ratio of speed of light in air to that in diamond is 2.42.

12. Define 1 dioptre of power of a lens.
Ans: 1 dioptre is the power of a lens whose focal length is 1 metre.
1 D = 1 m–¹

13. A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? Also find the power of the lens.
Ans: Here, v = +50 cm [vis positive for real image]
As the real image is of the same size as the object, so
m= h’/h = V/U =1
or,u = -v
       =-50 cm
Now,1/f = 1/v-1/u
               = (1/+50) – (1/-50)
               = + 2 / 50
               = + 1/ 25
or, f = 25 cm
        = 0.25 m
therefore, P = 1/f
                       =1 / +0.25 m
                       = +4 D

14.Find the power of a concave lens of focal length 2m.
Ans: Focal length of concave lens, f = -2m Power of concave lens, P = 1/f
                       therefore, P = 1/-2
                                             = – 0.5 D

15. (i) Which one of the following materials cannot be used to make a lens?
(a) water (b) glass (c) plastic (d) clay
Ans: (d)clay.

(ii) The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object?
(a) Between the principal focus and the centre of curvature.
(b) At the centre of curvature.
(c) Beyond the centre of curvature.
(d) Between the pole of the mirror and its principal focus.
Ans: (d) between the pole of the mirror and its principal focus.

(iii) A spherical mirror nd a then spherical lens have each focus length of 15 cm. The mirror and the lens are likely to be
(a) both Concave
(b) both convex
(c)the mirror is concave and the lens is convex,
(d) the mirror is convex,but the lens is concave
Ans : (a) both concave.

(iv) No matter how far you stand from a mirror, your image appears erect. The mirror Is likely to be.
(a) Plane (b) Concave (c) convex (d) either plane or convex.
Ans. (d) either plane or convex. 

(v) Which of the following lenses would you prefer to use while reading small letters found in a dictionary?
(a) A convex lens of focal length 50 cm.     
(b) A concave lens of focal length 50 cm.
(c) A convex lens of focal length 5 cm.
(d) A concave lens of focal length 5 cm.
Ans. (C) Convex lens of focal length 5 cm.

16. We Wish to obtain an erect image of an object, using a concave mirror of focal length 15 cm. What should be the range of distance of the object from the mirror? What is the nature of the image? Is the image larger or smaller than the object?Draw a ray diagram to show the image formation in this case.
Ans. Focal length of concave miror=15 cm.
Object should be placed in front of green concave
lmage formed is virtual and erect.
image size is larger than object.








17. Name the type of mirror used in the following situations,
(a) Head light of a car.
(b) Side/rear view mirror of a vehicle.
(c) Solar furnace. Support your answer with reason.
Ans: (a) For head light of a car : Use Concave mirror, to get a powerful beam of light after reflection.
(b) A convex mirror is used a side/rear view mirror of a vehicle. Convex mirror forms an erect and diminished image of vehicles and gives wider view of rear.
(C) In solar furnance concave mirror is used as a reflector, it concentrates sun light at a point where the temperature increases sharply to 180°C-200°C.

18. One-half of a convex lens is covered with a black paper. Will this lens produce a complete image of the object? Verify your answer experimentally? Explain your observation.
Ans. One-half of a convex lens when covered with a black paper, the lens produces a complete, full image of an object.
To verify experimentally:Take a convex lens, cover half part of it as shown in the figure, with a paper. Place it on a stand. Focus a distant object on a screen, the image obtained on the screen is complete.
Observation and conclusion : Image formed on the screen does not depend on the size of the lens. The brightness of the image decreases as less number of rays pass through the lens.

19. An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.
Ans:






20. A concave lens of local length 15 cm forms an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram.
Ans. Concave lens
         f= – 15 cm
        V= -10 cm
We know,
             1/v – 1/u = 1/f
        =>1/-10 – 1/u = 1/-15
          1/u = -1/30
             u = -30 cm
Ray diagram,






21. An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm.Find the position and nature of the image.
Ans:






The image is formed 6 cm behind the mirror virtual image is formed.

22. The magnification produced by a plane mirror is +1. What does this mean?
Ans. Magnification,m=+ 1
                             +indicates virtual image.
                           1 indicates that the size of the object and size of the image is same.

23. An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size.

Ans:






24. An object of size  7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm.at what distance from the mirror should a screen be placed,so that a sharp focussed image can be obtained? Find the size and the nature of the image.
Ans:






25. Find the focal length of a lens of power -2.0 D. What type of lens is this?Ans. P=-2.0 D.
         P=1/f
         f=1/P
          =1/-2.0D = -0.5 m.
The lens is concave lens as f= -ve.

26. A doctor has prescribed a corrective lens of power +1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?
Ans.p=+1.5 D,
  therefore,p=1/f
Focal length of the lens, f =1/P
                                              =1/+1.5D
                                              =+0.67 m
Power of the lens is ve, and it is converging lens i.e., Convex lens.




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